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A343963
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a(0) = 0, and for any n > 0, the binary expansion of n has n digits and starts with the binary expansion of n, say of w digits, and in case n > w, the remaining binary digits in a(n) are those of a(n-w).
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1
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0, 1, 2, 7, 9, 22, 55, 121, 137, 310, 695, 1529, 3209, 6966, 15031, 32249, 34297, 72841, 154422, 326327, 687609, 1410553, 2956425, 6183734, 12909239, 26902009, 55936505, 116202633, 241064758, 499448503, 1033534969, 2136311289, 2203420153, 4545387657
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OFFSET
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0,3
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COMMENTS
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To build the binary expansion of a(n):
- start with n indeterminate digits,
- while there are some, say m, indeterminate digits,
replace the first of them with the binary expansion of m.
The binary plot of the sequence has locally periodic patterns.
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LINKS
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FORMULA
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EXAMPLE
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For n = 10:
- the binary expansion of a(10) has 10 digits, and is the concatenation of:
- the binary expansion of 10 which is "1010",
- the binary expansion of 10 - 4 = 6 which is "110",
- the binary expansion of 10 - 4 - 3 = 3 which is "11",
- the binary expansion of 10 - 4 - 3 - 2 = 1 which is "1",
- as 10 = 4 + 3 + 2 + 1, we stop here,
- so the binary expansion of a(10) is "1010110111",
- and a(10) = 695.
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PROG
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(PARI) a(n) = { if (n==0, 0, my (k=n-#binary(n)); n*2^k+a(k)) }
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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