OFFSET
1,3
COMMENTS
The indices for which a(n) = 2^(n-2) appear to be A232803. - Michel Marcus, May 05 2021
This is true. We can check it for n <= 10. For n > 10 there are only primes and twice primes in A232803. Any number k > 10 not in A232803 can be factored as k = m*p where m, p > 2 and m >= p. We then have A343443(2^(m-2)*3^(p-2)) = m*p = k. But 2^(k-2) = 2^(m*p-2) > 2^(m-2)*3^(p-2). As m, p > 2 we have 2^(m-2)*3^(p-2) not in A232803. - David A. Corneth, May 05 2021
LINKS
David A. Corneth, Table of n, a(n) for n = 1..3325 (first 52 terms from Michel Marcus)
FORMULA
a(n) <= 2^(n-2) for n >= 3.
CROSSREFS
KEYWORD
nonn
AUTHOR
Michel Marcus, May 04 2021
STATUS
approved