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%I #8 Mar 03 2021 22:04:54
%S 2,5,11,176078293
%N Primes p dividing (the product of the primes less than p)-1.
%C The initial term 2 is included because the empty product minus 1 (which gives zero) is divisible by 2.
%e The prime 11 is included because 2*3*5*7-1 is divisible by 11. Therefore, the last factor of the product, namely 7, is in A341812.
%o (PARI) t=1;forprime(p=2,,((t-1)%p==0)&&print1(p,", ");t*=p)
%Y Cf. A058233, A066735, A341805, A341812.
%K nonn,hard,more
%O 1,1
%A _Jeppe Stig Nielsen_, Feb 20 2021
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