A328883 Denominators of the best rational approximations of log(6/5)/log(2).

1, 2, 3, 4, 11, 15, 19, 232, 251, 270, 289, 308, 327, 346, 365, 384, 403, 422, 1285, 1707, 2129, 3836, 28981, 32817, 36653, 40489, 44325, 48161, 51997, 3591629, 3643626, 3695623, 3747620, 3799617, 3851614, 3903611, 3955608, 4007605, 4059602, 4111599, 4163596, 4215593

Offset

1,2

Comments

A list of equal temperaments (equal divisions of the octave) whose nearest scale steps are closer and closer approximations to the ratios of two tones of musical harmony: the minor third, 6/5 and its complement the major sixth, 5/3.

The numerical value of each term represents a musical scale based on an equal division of the octave. 19, for example, signifies the scale which is formed by dividing the octave into 19 equal parts.

The 19 equal temperament, first proposed and used by Guillaume Costeley in the 16th century, uses 19 equally spaced tones, offering better major thirds and far better minor thirds than normal 12-semitone equal temperament at the cost of a flatter fifth.

Links

Table of n, a(n) for n=1..42.

Wikipedia, Guillaume Costeley

Index entries for sequences based on music

Prog

(Python 3)
import decimal
from math import floor
from decimal import Decimal as D
from collections import namedtuple
def continued_fraction(x, k):
    cf = []
    q = floor(x)
    cf.append(q)
    x = x - q
    i = 0
    while x != 0 and i < k:
        q = floor(1 / x)
        if q > k:
            break
        cf.append(q)
        x = 1 / x - q
        i += 1
    return cf
def best_rational_approximation(clist, app):
    hn0, kn0 = 0, 1
    hn1, kn1 = 1, 0
    ran, rad = 0, 0
    conlist, finallist = [], []
    fraction = namedtuple("fraction", "ratio, denom")
    for n in clist:
        for i in range(1, n + 1):
            ran = hn0 + (i * hn1)
            rad = kn0 + (i * kn1)
            try:
                if D.copy_abs(app-D(ran)/D(rad)) < D.copy_abs(app-D(hn1)/D(kn1)):
                    conlist.append(fraction(f'{ran}/{rad}', rad))
            except:
                pass
        hn2 = (n * hn1) + hn0
        kn2 = (n * kn1) + kn0
        conlist.append(fraction(f'{hn2}/{kn2}', kn2))
        hn0, kn0 = hn1, kn1
        hn1, kn1 = hn2, kn2
    #Change x.denom to x.ratio for the full ratio as a string
    finallist = [ x.denom for x in sorted(conlist, key=lambda i: i.denom) ]
    return list(dict.fromkeys(finallist))
if __name__ == "__main__":
    prec = 200
    decimal.getcontext().prec = prec
    value = D(6/5).ln()/D(2).ln()
    vc = continued_fraction(value, prec)
    print(', '.join([str(x) for x in best_rational_approximation(vc, value)]))

Crossrefs

Cf. A054540, A060525, A060526, A060527, A060528, A061918, A254351.

Sequence in context: A317913 A141704 A061919 * A192613 A002098 A301318

Adjacent sequences: A328880 A328881 A328882 * A328884 A328885 A328886

Keyword

nonn,frac

Author

Daniel Hoyt, Oct 29 2019

Status

approved