OFFSET
1,2
COMMENTS
A slow solution to Hofstadter V recurrence.
Numbers k such that a(k) < A063882(k) are 1654, 1721, 1925, ...
FORMULA
a(n+1) - a(n) = 0 or 1 for all n >= 1.
PROG
(PARI) q=vector(100); for(n=1, 7, q[n]=ceil(2*n/3)); for(n=8, #q, q[n]=q[n-q[n-1]] +q[n-q[n-4]]); q
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Altug Alkan, Aug 01 2019
STATUS
approved