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%I #32 Aug 27 2019 03:03:42
%S 0,1,2,3,4,5,6,7,8,9,10,13,20,21,23,31,41,42,43,46,51,53,61,62,63,71,
%T 73,81,82,83,84,86,91,93,100,101,102,110,111,112,113,114,115,116,117,
%U 118,119,121,122,123,131,133,141,144,151,155,158,161,166,171,177,181
%N Numbers k such that k in base 10 contains the same digits as k in some other base.
%C Supersequence of A034294 and A307498.
%C This sequence is infinite because 2*10^k is a term for any k >= 0.
%C Also 10^k is a term when k >= 0 and so too 10^k*(10^m - 1)/9 for any k > 0 and m >= 0. - _Bruno Berselli_, Aug 26 2019
%e k = 113 is in the sequence because the set of digits of k {1, 3} equals the set of digits of (k in base 110) = 13.
%o (PARI) isok(k) = {my(j=Set(digits(k))); for(b=2, k+1, if((b!=10) && (Set(digits(k, b)) == j), return(1))); return(0);} \\ _Michel Marcus_, Aug 05 2019
%Y Cf. A034294, A037415, A037422, A037428, A037433, A037437, A037440, A037442, A037443, A249899, A307498.
%K nonn,base
%O 1,3
%A _Jinyuan Wang_, Aug 05 2019
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