OFFSET
1,2
COMMENTS
This sequence might not be a permutation of A000027 (the positive numbers). After 18000 terms the smallest integer not yet present is 42. This 42 will perhaps never show.
From Rémy Sigrist, Jul 04 2018: (Start)
In fact, a(18420) = 42; however that this sequence is a permutation of the natural numbers remains an open question.
If we drop the unicity constraint, then we obtain A210025.
If moreover we impose that the sequence be nondecreasing, then we obtain A100787.
(End)
LINKS
Jean-Marc Falcoz, Table of n, a(n) for n = 1..15032
EXAMPLE
(The first members of the equalities hereunder must be seen as absolute differences between the successive pairs of adjacent terms:)
1 - 2 = 1
2 - 4 = 2
4 - 8 = 4
8 - 16 = 8
16 - 15 = 1
15 - 9 = 6
9 - 10 = 1
10 - 5 = 5
5 - 14 = 9
14 - 24 = 10
24 - 19 = 5
19 - 18 = 1, etc.
We see that the first and the last column present the same digit succession: 1, 2, 4, 8, 1, 6, 1, 5, 9, 1, 0, 5, 1, ...
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Eric Angelini and Jean-Marc Falcoz, Mar 27 2018
STATUS
approved