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a(n) = n^(n-1) + (n-1)!.
1

%I #17 Mar 21 2018 06:35:45

%S 2,3,11,70,649,7896,118369,2102192,43087041,1000362880,25941053401,

%T 743048287488,23298564124081,793721000274944,29193013203681825,

%U 1152922812281214976,48661212798456756481,2185911915426124627968,104127356700284947260841,5242880121645100408832000

%N a(n) = n^(n-1) + (n-1)!.

%H Seiichi Manyama, <a href="/A301347/b301347.txt">Table of n, a(n) for n = 1..387</a>

%F a(n) = A053042(n)/n.

%F a(n) = A000169(n) + A000142(n-1).

%t Array[#^(# - 1) + (# - 1)! &, 20] (* _Michael De Vlieger_, Mar 19 2018 *)

%o (PARI) a(n) = n^(n-1) + (n-1)! \\ _Altug Alkan_, Mar 19 2018

%Y Cf. A000142, A000169, A053042, A126130.

%K nonn

%O 1,1

%A _Seiichi Manyama_, Mar 19 2018