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A292740 Indices k such that A292547(k) = 0. 3

%I #13 Sep 23 2017 03:21:22

%S 2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,

%T 29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,

%U 52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70

%N Indices k such that A292547(k) = 0.

%C Complement of A290276.

%C Conjecture: for k > 212594 there are no more terms in this sequence (tested for k < 63000000).

%H Vaclav Kotesovec, <a href="/A292740/b292740.txt">Table of n, a(n) for n = 1..54766</a>

%e 3 is in the sequence because A292547(3) = 0

%e 8 is not in the sequence because A292547(8) = -1

%e 201254 is in the sequence because A292547(201254) = 0

%e 212594 is in the sequence because A292547(212594) = 0

%t With[{nn = 200}, -1 + Position[#, 0][[All, 1]] &@ CoefficientList[ Series[Product[1 + x^((2 k - 1)^3), {k, 1, Floor[nn^(1/3)/2] + 1}], {x, 0, nn}], x]] (* _Michael De Vlieger_, Sep 22 2017, after _Vaclav Kotesovec_ at A292547 *)

%Y Cf. A276517, A279329, A279486, A279529, A290276, A292547.

%Y Cf. A001476, A022555, A031980.

%K nonn

%O 1,1

%A _Vaclav Kotesovec_, Sep 22 2017

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