%I #4 May 20 2017 21:53:36
%S 1,2,3,4,5,6,8,9,10,11,12,13,15,16,17,18,19,20,21,22,23,25,26,27,28,
%T 29,30,32,33,34,35,36,37,38,39,40,42,43,44,45,46,47,49,50,51,52,53,54,
%U 56,57,58,59,60,61,62,63,64,66,67,68,69,70,71,73,74,75,76
%N Positions of 0 in A286996; complement of A188383.
%C a(n) - a(n-1) is in {1,2} for n>=2, and a(n)/n -> (2 + sqrt(2))/3.
%H Clark Kimberling, <a href="/A286997/b286997.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A286993 = 11000110001000110..., in which 0 is in positions 1,2,3,4,5,6,8,....
%t s = Nest[Flatten[# /. {0 -> 1, 1 -> {1, 1, 0}}] &, {1}, 11]; (* Sturmian word A080764 *)
%t w = StringJoin[Map[ToString, s]];
%t w1 = StringReplace[w, {"0" -> "000", "11"->""}]
%t st = ToCharacterCode[w1] - 48 ; (* A286996 *)
%t Flatten[Position[st, 0]]; (* A286997 *)
%t Flatten[Position[st, 1]]; (* A188383 *)
%Y Cf. A080764, A286996, A188383.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, May 20 2017