%I #7 Mar 15 2019 10:49:35
%S 1,3,5,6,8,9,11,13,15,16,18,20,21,23,25,26,28,29,31,33,34,36,38,39,41,
%T 43,45,46,48,49,51,53,55,56,58,60,61,63,65,66,68,70,72,73,75,76,78,80,
%U 81,83,85,86,88,89,91,93,95,96,98,100,101,103,105,106,108
%N Positions of 0 in A285966; complement of A285968.
%C Conjecture: a(n)/n -> 5/3.
%C For a proof of this conjecture see A285968. - _Michel Dekking_, Mar 15 2019
%H Clark Kimberling, <a href="/A285967/b285967.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A285966 = 01010010010101001010010..., in which 0 is in positions 1,3,5,6,8,...
%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0}}] &, {0}, 9] (* Thue-Morse, A010060 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"11" -> "1"}]
%t st = ToCharacterCode[w1] - 48 (* A285966 *)
%t Flatten[Position[st, 0]] (* A285967 *)
%t Flatten[Position[st, 1]] (* A285968 *)
%Y Cf. A010060, A285966, A285968.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, May 06 2017