OFFSET
0,14
COMMENTS
This sequence is conjecturally 41190-regular.
LINKS
Eric Rowland, Table of n, a(n) for n = 0..20000
Lara Pudwell and Eric Rowland, Avoiding fractional powers over the natural numbers, arXiv:1510.02807 [math.CO] (2015).
Eric Rowland, List of first 400000 terms
FORMULA
Conjecture: a(41190 n + 41201) = a(n) + 3.
CROSSREFS
KEYWORD
nonn
AUTHOR
Eric Rowland, Oct 01 2016
STATUS
approved