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A275932
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a(n) = F(2*n+6)*F(2*n+2)^3, where F = Fibonacci (A000045).
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1
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8, 567, 28160, 1333584, 62723375, 2947166208, 138457523672, 6504579992295, 305576963500544, 14355613810692000, 674408279720748383, 31682833585030397952, 1488418770572887642280, 69923999385781980681879, 3284939552377913067968000, 154322234962490820966855408
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OFFSET
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0,1
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COMMENTS
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The right-hand side of Helmut Postl's identity F(2n+6) + F(n)*F(n+4)^3 = F(n+6)*F(n+2)^3, n even.
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LINKS
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FORMULA
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a(n) = 55*a(n-1)-385*a(n-2)+385*a(n-3)-55*a(n-4)+a(n-5) for n>4.
G.f.: (8+127*x+55*x^2-x^3) / ((1-x)*(1-47*x+x^2)*(1-7*x+x^2)).
(End)
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MATHEMATICA
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Table[(Fibonacci[2 n + 6] Fibonacci[2 n + 2]^3), {n, 0, 20}] (* Vincenzo Librandi, Sep 02 2016 *)
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PROG
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(PARI) Vec((8+127*x+55*x^2-x^3)/((1-x)*(1-47*x+x^2)*(1-7*x+x^2)) + O(x^20)) \\ Colin Barker, Aug 31 2016
(Magma) [Fibonacci(2*n+6)*Fibonacci(2*n+2)^3: n in [0..25]]; // Vincenzo Librandi, Sep 02 2016
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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