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A272718
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Partial sums of gcd-sum sequence A018804.
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10
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1, 4, 9, 17, 26, 41, 54, 74, 95, 122, 143, 183, 208, 247, 292, 340, 373, 436, 473, 545, 610, 673, 718, 818, 883, 958, 1039, 1143, 1200, 1335, 1396, 1508, 1613, 1712, 1829, 1997, 2070, 2181, 2306, 2486, 2567, 2762, 2847, 3015, 3204, 3339, 3432, 3672, 3805, 4000, 4165
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OFFSET
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1,2
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COMMENTS
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a(n) is the sum of all pairs of greater common divisors for (i,j) where 1 <= i <= j <= n. - Jianing Song, Feb 07 2021
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LINKS
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FORMULA
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According to Bordellès (2007), a(n) = (n^2 / (2*zeta(2)))*(log n + gamma - 1/2 + log(A^12/(2*Pi))) + O(n^(1+theta+epsilon)) where gamma = A001620, A ~= 1.282427129 is the Glaisher-Kinkelin constant A074962, theta is a certain constant defined in terms of the divisor function and known to lie between 1/4 and 131/416, and epsilon is any positive number.
G.f.: (1/(1 - x))*Sum_{k>=1} phi(k)*x^k/(1 - x^k)^2, where phi(k) is the Euler totient function. - Ilya Gutkovskiy, Jan 02 2017
a(n) = (1/2)*Sum_{k=1..n} phi(k) * floor(n/k) * floor(1+n/k), where phi(k) is the Euler totient function. - Daniel Suteu, May 28 2018
a(n) = Sum_{i=1..n, j=i..n} gcd(i,j).
a(n) = (A018806(n) + n*(n+1)/2) / 2 = (Sum_{k=1..n} phi(k)*(floor(n/k))^2 + n*(n+1)/2) / 2, phi = A000010.
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EXAMPLE
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The gcd-sum function takes values 1,3,5 for n=1,2,3; therefore a(3) = 1+3+5=9.
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MATHEMATICA
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b[n_] := GCD[n, #]& /@ Range[n] // Total;
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PROG
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(PARI) first(n)=my(v=vector(n), f); v[1]=1; for(i=2, n, f=factor(i); v[i] = v[i-1] + prod(j=1, #f~, (f[j, 2]*(f[j, 1]-1)/f[j, 1] + 1)*f[j, 1]^f[j, 2])); v \\ Charles R Greathouse IV, May 05 2016
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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