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A265738
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Integers k such that k!3 is divisible by k^3, where k!3 = k!!! is a triple factorial number (A007661).
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0
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1, 18, 27, 36, 40, 45, 48, 54, 56, 60, 63, 64, 70, 72, 75, 77, 80, 81, 84, 88, 90, 91, 96, 98, 99, 100, 104, 105, 108, 110, 112, 117, 119, 120, 125, 126, 128, 130, 132, 133, 135, 136, 140, 143, 144, 147, 150, 152, 153, 154, 156, 160, 161, 162, 165, 168, 169, 170, 171, 175, 176
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OFFSET
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1,2
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COMMENTS
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Obviously, a(n) cannot be a prime number. 77 is the first term which is semiprime.
Numbers of the form 9*t are terms of this sequence for t > 1.
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LINKS
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EXAMPLE
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18 is a term because 18!!! = 524880 and 524880 mod 18^3 = 0.
27 is a term because 27!!! = 7142567040 and 7142567040 mod 27^3 = 0.
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PROG
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(PARI) tf(n) = prod(i=0, (n-1)\3, n-3*i);
k(n) = tf(n) % n^3;
for(n=1, 1e3, if(k(n)==0, print1(n, ", ")))
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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