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Inverse Mobius Transform of A002654.
1

%I #11 Sep 14 2019 14:56:21

%S 1,2,1,3,3,2,1,4,2,6,1,3,3,2,3,5,3,4,1,9,1,2,1,4,6,6,2,3,3,6,1,6,1,6,

%T 3,6,3,2,3,12,3,2,1,3,6,2,1,5,2,12,3,9,3,4,3,4,1,6,1,9,3,2,2,7,9,2,1,

%U 9,1,6,1,8,3,6,6,3,1,6,1,15,3,6,1,3,9

%N Inverse Mobius Transform of A002654.

%F Conjecture: multiplicative with a(p^e) = 1 if p=2; a(p^e) = 0 if e odd and p in A002145; a(p^e) = 1 if e even and p in A002145; a(p^e) = e+1 if p in A002144.

%F G.f.: Sum_{k>=1} tau(k)*x^k/(1 + x^(2*k)), where tau = A000005. - _Ilya Gutkovskiy_, Sep 14 2019

%Y Cf. A000005, A002144, A002145, A002654.

%K nonn,mult,easy

%O 1,2

%A _R. J. Mathar_, Sep 15 2015