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a(n) = sqrt(A261655(n)/144) for n>1.
1

%I #8 Sep 22 2015 05:00:42

%S 1,3,5,35,33,144,80,137,285,363,387,351,204,935,225,241,289,665,1210,

%T 310,710,324,327,685,945,749,805,479,2091,1260,1169,628,2156,654,2355,

%U 1827,1545,2181,1499,761,3126,1575,2364,1770,1452,1455,2827,1739,3390,4641

%N a(n) = sqrt(A261655(n)/144) for n>1.

%C The primes of the sequence are 3, 5, 137, 241, 479, 761, 1499, ...

%C The squares of the sequence are 1, 144, 225, 289, 324, ...

%e a(3)=3 because sqrt(A261655(3)/144) = sqrt(1296/144) = sqrt(9)=3.

%p q:=83:for n from 2 to 10^7 do:p:=n^2+2:if isprime(p) then x:=p-q:q:=p: z:=sqrt(x):if z=floor(z) then printf(`%d, `, x/144):else fi:fi:od:

%Y Cf. A261655: squares equal to the difference between two successive primes of the form k^2+2.

%K nonn

%O 2,2

%A _Michel Lagneau_, Aug 28 2015