|
%I #31 Jun 16 2015 19:19:31
%S 1,3,9,48,4,8,9,9,6,5,5,0,28,70,0,89,11,48,5,8,7,8,53,3,0,26,4,6,5,9,
%T 5,8,26,3,6,20,9,1,3,43,6,86,43,4,0,0,80,7,4,4,9,1,3,86,4,77,4,70,8,
%U 74,4,2,7,6,9,88,74,7,57,8,4,0,0,28,4,62,3,4,170,6,69,87,2
%N Whole number sieve of Phi.
%H Manfred Scheucher, <a href="/A258481/b258481.txt">Table of n, a(n) for n = 1..550</a>
%H Manfred Scheucher, <a href="/A258481/a258481.sage.txt">Sage Script</a>
%e Find the first occurrence of 0 (the first whole number) in the digits of Phi (only 35 digits in this illustration):
%e 16180339887498948482045868343656381..., and replace it with a space:
%e 1618 339887498948482045868343656381... Repeat the process with the next whole number, 1:
%e 618 339887498948482045868343656381... Then 2:
%e 618 33988749894848 045868343656381... Then 3:
%e 618 3988749894848 045868343656381... Then 4,5,6,7, etc., until the first occurrence of every counting number is eliminated from the digits of Phi.
%e 1 3 9 48 04 8 ... Then consolidate gaps between the remaining digits into a single comma:
%e 1,3,9,48,4,8,9,9,6,5,5,0,28,70,0, ... to produce the first terms in the whole number sieve of Phi.
%Y Cf. A001622, A247861, A247747, A257835, A258640.
%K nonn,easy,base
%O 1,2
%A _Manfred Scheucher_, Jun 05 2015
|
