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a(n) = 3*binomial(n+1,7).
0

%I #52 Sep 08 2022 08:46:11

%S 3,24,108,360,990,2376,5148,10296,19305,34320,58344,95472,151164,

%T 232560,348840,511632,735471,1038312,1442100,1973400,2664090,3552120,

%U 4682340,6107400,7888725,10097568,12816144,16138848,20173560,25043040,30886416,37860768

%N a(n) = 3*binomial(n+1,7).

%C For a set of integers {1,2,...,n}, a(n) is the sum of the 2 smallest elements of each subset with 6 elements, which is 3*C(n+1,7) (for n>=6), hence a(n) = 3*C(n+1,7) = 3*A000580(n+1).

%H Serhat Bulut and Oktay Erkan Temizkan, <a href="http://matematikproje.com/dosyalar/7e1cdSubset_smallest_elements_Sum.pdf">Subset Sum Problem</a>

%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (8,-28,56,-70,56,-28,8,-1).

%F a(n) = 3*C(n+1,7) = 3*A000580(n+1).

%F a(n) = 3*C(n+1,7) = (n^7 - 14n^6 + 70n^5 - 140n^4 + 49n^3 + 154n^2 - 120n)/1680.

%e For A={1,2,3,4,5,6,7}, subsets with 6 elements are {1,2,3,4,5,6}, {1,2,3,4,5,7}, {1,2,3,4,6,7}, {1,2,3,5,6,7}, {1,2,4,5,6,7}, {1,3,4,5,6,7}, {2,3,4,5,6,7}.

%e Sum of 2 smallest elements of each subset:

%e a(7) = (1+2)+(1+2)+(1+2)+(1+2)+(1+2)+(1+3)+(2+3) = 24 = 3*C(7+1,7) = 3*A000580(7+1).

%t Drop[Plus @@ Flatten[Part[#, 1 ;; 2] & /@ Subsets[Range@ #, {6}]] & /@

%t Range@ 28, 5] (* _Michael De Vlieger_, Jan 20 2015 *)

%t 3 Binomial[Range[7, 29], 7] (* _Michael De Vlieger_, Feb 13 2015, after _Alonso del Arte_ at A253946 *)

%o (PARI) a(n)=3*binomial(n+1,7) \\ _Charles R Greathouse IV_, Feb 04 2015

%o (Magma) [3*Binomial(n+1, 7): n in [6..40]]; // _Vincenzo Librandi_, Feb 13 2015

%K nonn,easy

%O 6,1

%A _Serhat Bulut_, Jan 20 2015

%E More terms from _Vincenzo Librandi_, Feb 13 2015

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Last modified September 21 22:57 EDT 2024. Contains 376090 sequences. (Running on oeis4.)