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A250154
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T(n,k)=Number of length n+6 0..k arrays with every seven consecutive terms having the maximum of some two terms equal to the minimum of the remaining five terms
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15
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107, 1452, 193, 9160, 3450, 354, 37805, 26710, 8377, 654, 119391, 129595, 79740, 20513, 1212, 313852, 468231, 455055, 240144, 50228, 2248, 722072, 1382188, 1879526, 1611449, 721644, 122228, 4166, 1501425, 3522460, 6219899, 7601062
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OFFSET
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1,1
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COMMENTS
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Table starts
...107....1452......9160......37805......119391.......313852.......722072
...193....3450.....26710.....129595......468231......1382188......3522460
...354....8377.....79740.....455055.....1879526......6219899.....17519352
...654...20513....240144....1611449.....7601062.....28153337.....87461488
..1212...50228....721644....5682771....30540568....126272510....431428872
..2248..122228...2144132...19726379...120228940....552269862...2065373112
..4166..293972...6242596...66600911...456748018...2312181994...9388944776
..7702..694228..17629584..215884055..1647466166...9084404402..39584158608
.14270.1665492..51324016..733377115..6339887238..38812476262.185122408752
.26488.4027873.150838232.2521174765.24740345120.168394122957.879922285648
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LINKS
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FORMULA
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Empirical for column k:
k=1: [linear recurrence of order 42]
Empirical for row n:
n=1: a(n) = (7/2)*n^6 + 14*n^5 + (105/4)*n^4 + (63/2)*n^3 + (91/4)*n^2 + 8*n + 1
n=2: [polynomial of degree 7]
n=3: [polynomial of degree 8]
n=4: [polynomial of degree 9]
n=5: [polynomial of degree 10]
n=6: [polynomial of degree 11]
n=7: [polynomial of degree 11]
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EXAMPLE
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Some solutions for n=3 k=4
..0....0....0....0....0....1....0....0....1....0....1....1....0....1....0....0
..3....1....1....4....2....1....1....3....0....2....0....1....1....0....4....3
..3....3....1....0....0....0....1....3....2....0....0....1....0....0....1....1
..4....1....1....0....0....0....0....3....0....0....2....1....0....1....1....3
..1....3....1....3....3....2....1....4....1....4....2....1....2....4....1....2
..1....4....2....1....2....0....0....0....3....0....1....3....1....0....2....1
..4....1....1....2....0....2....1....0....0....1....0....4....2....0....3....4
..0....0....1....0....4....3....0....0....0....2....0....2....0....4....1....1
..3....2....0....0....4....0....3....4....2....0....1....4....3....0....2....0
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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