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A249562 Number of length n permutations avoiding (123,{2},{}) and (123,{},{1}). 4
1, 1, 2, 5, 14, 43, 143, 509, 1921, 7631, 31725, 137412, 617822, 2874819, 13809305, 68331089, 347657464, 1815839759, 9722708061, 53301771604, 298854490602, 1712023130016, 10011533550216, 59714205975048, 363008132101658, 2247599137530241, 14164805684388087, 90810818671081267, 591921142070249872 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
(123,{2},{}) is a vincular pattern. It has underlying classical pattern 123 and the extra requirement that the 2 and the 3 are adjacent in the permutation.
(123,{},{1}) is a co-vincular pattern. It has underlying classical pattern 123 and the extra requirement that the 1 and 2 are exactly one apart in the permutation.
LINKS
Christian Bean, Sage code
Christian Bean, A Claesson, H Ulfarsson, Simultaneous Avoidance of a Vincular and a Covincular Pattern of Length 3, arXiv preprint arXiv:1512.03226 [math.CO], 2015.
Zhicong Lin, Sherry H. F. Yan, Vincular patterns in inversion sequences, Applied Mathematics and Computation (2020), Vol. 364, 124672.
FORMULA
If x appears after x-1 in the permutation then we say that x is a ceiling point.
if i = 1: aup(n,k,i,l) = sum( abar(n,k,i,l) for m in [0..k] )
otherwise: aup(n,k,i,l) = sum( abar(n-1,k,1,m) for m in [l..k] ) + sum( sum( adown(n-1,k,j,m) for m in [i..k]) for j in [1..i-1] )
abar(n,k,i,l) = sum( a(n-1,k-1,j,l-1) for j in [1..k-1] )
adown(n,k,i,l) = sum( aup(n-1,k,j,l) + adown(n-1,k,j,l) for j in [i..k] )
a(n,k,i,l) = aup(n,k,i,l) + adown(n,k,i,l) + abar(n,k,i,l)
where n is the length, k is the number of left to right minima, i is the position of the maximum, l is the position of the first ceiling point
aup implies that max is a ceiling point, abar implies that max is a left to right minimum and adown implies max is neither.
Initial conditions: if i > l or k > n or i > k or l > k then aup(n,k,i,l) = adown(n,k,i,l) = 0, if i < l or l <= 0 then aup(n,k,i,l) = 0, if n - k = 1 then a(n,k,i,l) = 1, if i does not equal 1 the abar(n,k,i,l) = 0, abar(n,n,1,0) = 1.
a(n) = sum( sum( sum( a(n,k,j,m) for m in [0..k] ) for j in [1..k] ) for k in [1..n] )
CROSSREFS
Sequence in context: A155888 A366099 A254314 * A006789 A202060 A098569
KEYWORD
nonn
AUTHOR
Christian Bean, Nov 01 2014
STATUS
approved

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Last modified April 25 05:18 EDT 2024. Contains 371964 sequences. (Running on oeis4.)