%I #8 Oct 25 2014 14:56:54
%S 13,5,7,3,11,13,5,17,19,7,23,28081,31,11,131,13,41,43,5,47,4951,53,
%T 5557,59,61,7,218923,71,73,7577,79,3,83,85878991939597,11,101,103,
%U 105107,109,37,113,115117
%N Primes corresponding to terms of A248145.
%F There exists k=k(n)>=0, such that the number 3^k*a(n) is a concatenation of A248145(n) consecutive odd numbers.
%Y Cf. A248145.
%K nonn
%O 1,1
%A _Vladimir Shevelev_, Oct 02 2014