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%I #6 Dec 12 2014 20:22:15
%S 32,203,64,824,529,128,2365,2760,1387,256,5496,9569,9248,3649,512,
%T 11167,25512,38753,31092,9611,1024,20648,57769,118416,157589,104692,
%U 25265,2048,35249,117256,298267,552708,641575,352744,66443,4096,56960,216937,663080
%N T(n,k)=Number of length n+4 0..k arrays with some disjoint pairs in every consecutive five terms having the same sum
%C Table starts
%C ....32.....203......824......2365.......5496.......11167........20648
%C ....64.....529.....2760......9569......25512.......57769.......117256
%C ...128....1387.....9248.....38753.....118416......298267.......663080
%C ...256....3649....31092....157589.....552708.....1551533......3785236
%C ...512....9611...104692....641575....2582556.....8083791.....21652632
%C ..1024...25265...352744...2609703...12052496....42077905....123827876
%C ..2048...66443..1189016..10628145...56329528...219338895....709026892
%C ..4096..174817..4008988..43309569..263412952..1144120333...4062290944
%C ..8192..460139.13519544.176541467.1232134860..5970696303..23284325652
%C .16384.1211409.45597176.719680843.5763691618.31162093065.133483154922
%H R. H. Hardin, <a href="/A247927/b247927.txt">Table of n, a(n) for n = 1..2022</a>
%F Empirical for column k:
%F k=1: a(n) = 2*a(n-1)
%F k=2: [order 12]
%F k=3: [order 79]
%F Empirical for row n:
%F n=1: a(n) = 2*a(n-1) -a(n-3) -2*a(n-5) +2*a(n-6) +a(n-8) -2*a(n-10) +a(n-11); also a polynomial of degree 4 plus a linear quasipolynomial with period 12
%F n=2: [order 27; also a polynomial of degree 5 plus a linear quasipolynomial with period 420]
%e Some solutions for n=4 k=4
%e ..1....2....2....1....2....2....2....1....1....3....2....1....2....0....1....2
%e ..3....3....3....2....3....1....3....2....2....0....3....1....4....3....4....3
%e ..1....4....4....4....4....1....4....3....3....2....2....1....0....4....0....2
%e ..3....3....3....3....0....4....3....0....1....0....3....0....2....4....3....0
%e ..0....2....0....3....1....4....1....1....4....1....3....1....4....0....1....1
%e ..2....3....0....0....3....1....2....3....4....3....4....1....2....0....4....1
%e ..3....0....4....2....0....4....0....0....3....0....2....0....1....4....2....2
%e ..4....2....1....0....2....1....4....4....0....2....0....4....4....4....2....0
%Y Column 1 is A000079(n+4)
%K nonn,tabl
%O 1,1
%A _R. H. Hardin_, Sep 26 2014
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