|
%I #15 May 10 2013 16:20:57
%S 15,33,88,175,1127,3465,7029,36659,1755164,4900901,537252430,
%T 816292168,1365815759,2048921480,11937573274,14434878293,17435497255,
%U 27826547235,169697066625,371707331522,405119159125,800760189610,23737435535625,86561181062463,100528900924040
%N Numbers n such that 9n is a partition number.
%F a(j) = A225360(j)/9.
%e 15 is in the sequence because 9*15 = 135 and 135 is a partition number: p(14) = A000041(14) = 135.
%t Select[PartitionsP[Range[300]], Mod[#, 9] == 0 &]/9 (* _T. D. Noe_, May 05 2013 *)
%Y Cf. A000041, A213179, A213365, A216258, A217725, A217726, A222175, A222178, A225317, A225323, A225360.
%K nonn
%O 1,1
%A _Omar E. Pol_, May 05 2013
%E a(6)-a(25) from _R. J. Mathar_, May 05 2013
|
