OFFSET
1,2
COMMENTS
The theorem on page 7 of Stanton and Holdener gives conditions for a rational to be an abundancy outlaw.
For a given n, these conditions have been checked by starting with m/n=sigma(n)/n and then increasing m until they fail.
LINKS
Michel Marcus, Table of n, a(n) for n = 1..1000
William G. Stanton and Judy A. Holdener, Abundancy "Outlaws" of the Form (sigma(N) + t)/N, Journal of Integer Sequences , Vol 10 (2007) , Article 07.9.6.
EXAMPLE
a(3) = 4 because 4/3 is the abundancy index of 3, so 4/3 is not an abundancy outlaw.
CROSSREFS
KEYWORD
nonn
AUTHOR
Michel Marcus, Jul 22 2012
STATUS
approved