1,2

Clark Kimberling, Table of n, a(n) for n = 1..1000

a(7) = 4 because 3^7 < 7! <= 4^7.

Table[m=1; While[n!>m^n, m++]; m, {n, 1, 100}]

Cf. A214045.

Sequence in context: A245473 A306904 A057362 * A085269 A173276 A288156

Adjacent sequences: A214043 A214044 A214045 * A214047 A214048 A214049

nonn,easy

Clark Kimberling, Jul 18 2012

approved