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A186516 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=4+5j^2. Complement of A186515. 4

%I #5 Mar 30 2012 18:57:19

%S 3,6,9,13,16,19,22,25,29,32,35,38,42,45,48,51,55,58,61,64,67,71,74,77,

%T 80,84,87,90,93,97,100,103,106,110,113,116,119,122,126,129,132,135,

%U 139,142,145,148,152,155,158,161,165,168,171,174,177,181,184,187,190,194,197,200,203,207,210,213,216,220,223,226,229,233,236,239,242,245,249,252,255,258,262,265,268,271

%N Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=4+5j^2. Complement of A186515.

%C See A186219 for a discussion of adjusted joint rank sequences.

%C The pairs (i,j) for which i^2=4+5j^2 are (L(2h),F(2h)), where L=A000032 (Lucas numbers) and F=A000045 (Fibonacci numbers).

%F a(n)=n+floor(sqrt((n^2)/5-7/10))=A186515(n).

%F b(n)=n+floor(sqrt(5n^2+7/2))=A186516(n).

%e First, write

%e 1..4..9..16..25..36..49.. (i^2)

%e ......9.....24.......49.. (4+5j^2)

%e Then replace each number by its rank, where ties are settled by ranking i^2 after 4+5j^2:

%e a=(1,2,4,5,7,8,10,11,12,14,15,17,..)=A186515

%e b=(3,6,9,13,16,19,22,25,29,32,35,..)=A186516.

%t (See A186515.)

%Y Cf. A186219, A186513, A186514, A186515.

%K nonn

%O 1,1

%A _Clark Kimberling_, Feb 22 2011

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Last modified May 2 04:48 EDT 2024. Contains 372178 sequences. (Running on oeis4.)