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A178829
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Partial sums of (1/2)*floor(7^n/10).
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1
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0, 2, 19, 139, 979, 6861, 48038, 336278, 2353958, 16477720, 115344057, 807408417, 5651858937, 39563012579, 276941088076, 1938587616556, 13570113315916, 94990793211438, 664935552480095, 4654548867360695
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OFFSET
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1,2
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LINKS
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FORMULA
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a(n) = round((7*7^n - 30*n - 25)/60)/2.
a(n) = floor((7*7^n - 30*n - 7)/60)/2.
a(n) = ceiling((7*7^n - 30*n - 43)/60)/2.
a(n) = a(n-4) + 20*7^(n-3) - 1 , n > 4.
a(n) = (7^(n+1) - 30*n + 6*(2+(-1)^n)*(-1)^((2*n-1+(-1)^n)/4)-25)/120.
G.f.: x^2*(2+x)/((1-7*x)*(1+x^2)*(1-x)^2). (End)
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EXAMPLE
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a(3) = (1/2)*(floor(7/10) + floor(49/10) + floor(343/10))
= (1/2)*(0 + 4 + 34) = (1/2)*38 = 19.
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MAPLE
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seq(1/2*floor((7*7^n-30*n-7)/60), n=1..25);
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MATHEMATICA
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CoefficientList[Series[x(2+x)/((1-7x)(1+x^2)(1-x)^2), {x, 0, 50}], x] (* Vincenzo Librandi, Mar 26 2014 *)
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PROG
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(Magma) [(1/2*Floor((7*7^n-30*n-7)/60)): n in [1..30]]; // Vincenzo Librandi, Jun 21 2011
(PARI) my(x='x+O('x^30)); concat([0], Vec(x^2*(2+x)/((1-7*x)*(1+x^2)*(1-x)^2))) \\ G. C. Greubel, Jan 22 2019
(Sage) a=(x^2*(2+x)/((1-7*x)*(1+x^2)*(1-x)^2)).series(x, 30).coefficients(x, sparse=False); a[1:] # G. C. Greubel, Jan 22 2019
(GAP) a:=List([1..25], n->(1/2)*Int((7*7^n-30*n-7)/60));; Print(a); # Muniru A Asiru, Jan 22 2019
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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