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%I #20 Sep 08 2022 08:45:49
%S 0,1,65664,64573362,8589967360,381469921875,8463330562176,
%T 116315259876004,1125899915231232,8338590871356645,50000000050000000,
%U 252723514356826326,1109305553585209344,4325207960098534327
%N a(n) = n^8*(n^9 + 1)/2.
%H Vincenzo Librandi, <a href="/A170781/b170781.txt">Table of n, a(n) for n = 0..10000</a>
%H <a href="/index/Rec#order_18">Index entries for linear recurrences with constant coefficients</a>, signature (18,-153,816,-3060,8568,-18564, 31824,-43758,48620,-43758,31824,-18564,8568,-3060,816,-153,18,-1).
%F G.f.: x*(65408*x^15 + 63389457*x^14 + 7437706830*x^13 + 236676646043*x^12 + 2858645937996*x^11 + 15527826613305*x^10 + 41568611448626*x^9 + 57445190329275*x^8 + 41568611736744*x^7 + 15527826335083*x^6 + 2858646034386*x^5 + 236676655017*x^4 + 7437692620*x^3 + 63391563*x^2 + 65646*x + 1) / (1-x)^18. - _Colin Barker_, Nov 24 2012
%t Table[n^8(n^9+1)/2, {n,0,20}] (* _Harvey P. Dale_, Oct 24 2011 *)
%o (Magma) [n^8*(n^9+1)/2: n in [0..30]]; // _Vincenzo Librandi_, Aug 26 2011
%o (PARI) for(n=0, 30, print1(n^8*(n^9+1)/2, ", ")) \\ _G. C. Greubel_, Dec 05 2017
%K nonn,easy
%O 0,3
%A _N. J. A. Sloane_, Dec 11 2009
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