%I
%S 1,2,6,12,576000
%N Let b(n,k) = the kth binary digit (starting at k=1, reading right to left) in the base 2 representation of n. (So: n = sum{k>=0} b(k+1)*2^k.) A positive integer n is included in this sequence if and only if n = product{k>=1} k^b(n,k).
%C Hans Havermann found term a(5).
%C Jack Brennen says that there are no other terms < 2^32.
%C a(6) > 2^80 if it exists.  _Bert Dobbelaere_, Apr 19 2019
%e 12 in binary is 1100. And 12 = 4^1 * 3^1 * 2^0 * 1^0. So 12 is in the sequence.
%K base,more,nonn
%O 1,2
%A _Leroy Quet_, Jun 07 2009
