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Continued fraction expansion of Landau's constant L.
1

%I #5 Dec 19 2015 23:16:47

%S 0,1,1,5,3,1,1,2,1,1,6,3,1,8,11,2,1,1,27,4,1,1,2,3,3,3,1,1,4,1,3,11,1,

%T 1,3,1,1,1,2,3,26,10,3,1,3,1,1,1,2,2,2,1,1,1,7,4,1,2,2,1,1,6,2,10,2,6,

%U 6,1,3,1,2,4,2,1,2,5,1,1,1,1,1,4,11,9,1,1,1,2,1,2,5,2,4,1,48,1,8,1,8,7,1,3

%N Continued fraction expansion of Landau's constant L.

%C Terms are computed using the conjectured formula.

%H Harry J. Smith, <a href="/A159671/b159671.txt">Table of n, a(n) for n = 0..1000</a>

%F It is conjectured that L = 0.5432589653429767... = Gamma(1/3)*Gamma(5/6)/Gamma(1/6).

%e L = 0.543258965342976706952728...= 0 + 1/(1 + 1/(1 + 1/(5 + 1/(3 + ...)))).

%o (PARI) { default(realprecision, 1080); x=contfrac(gamma(1/3)*gamma(5/6)/gamma(1/6)); d=0; for (n=0, 1000, write("b159671.txt", n, " ", x[n+1])); }

%K nonn

%O 0,4

%A _Harry J. Smith_, Apr 19 2009

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