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%I #7 Mar 11 2014 01:32:23
%S 1,1,2,1,2,1,2,3,1,2,1,2,3,1,2,1,2,3,1,2,3,4,5,1,2,1,2,3,1,2,1,2,3,1,
%T 2,3,4,5,1,2,1,2,3,1,2,1,2,3,1,2,3,4,5,1,2,1,2,3,1,2,3,4,5,1,2,3,4,5,
%U 6,7,1,2,3,4,5,6,7,8,9,10,11,1,2,1,2,3,1,2,1,2,3,1,2,3,4,5,1,2,1,2,3,1,2,1
%N a(1) = 1. After the initial 1, follow with runs of integers; the n-th run of p(a(n)) terms is (1,2,3,4,....,p(a(n))), where p(m) is the m-th prime.
%e Runs of integers bracketed by parentheses. (Note that n-th run {after the initial 1} has exactly p(a(n)) terms.)
%e 1,(1,2),(1,2),(1,2,3),(1,2),(1,2,3),(1,2),(1,2,3),(1,2,3,4,5),(1,2),(1,2,3),(1,2),(1,2,3),(1,2,3,4,5),(1,2),(1,2,3),(1,2),(1,2,3),(1,2,3,4,5),(1,2),(1,2,3),(1,2,3,4,5),(1,2,3,4,5,6,7),(1,2,3,4,5,6,7,8,9,10,11),...
%K nonn
%O 1,3
%A _Leroy Quet_, Mar 15 2008
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