OFFSET
1,2
COMMENTS
The number in question has 9956570551809674817234887108108339491770560299419 \ 63334338855462168341353507911292252707750506615682568 digits and ends in exactly 10^101/8 - 18 zeros. - Robert G. Wilson v, Jan 09 2013
The last nonzero term of this sequence is 6. - Washington Bomfim, Dec 24 2010
REFERENCES
Ronald L. Graham, Donald E. Knuth and Oren Patashnik, Concrete Math.; section 4, exercises 40, and 54.
FORMULA
10^100! = 1*2*3*4*...*(10^100-1)*10^100.
MATHEMATICA
f[n_] := 10^FractionalPart[N[(n*Log[n] - n + (1/2)*Log[(2*n + 1/3)*Pi])/Log[10], 203]]; RealDigits[ f[10^100], 10, 101][[1]] (* Robert G. Wilson v, Jan 09 2013 *)
CROSSREFS
KEYWORD
AUTHOR
Martin Raab, Nov 18 2007, Dec 11 2007
STATUS
approved