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A129745
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Numbers k such that Lucas(4k)/7 is prime.
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0
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5, 17, 19, 41, 43, 71, 1511, 2339, 3469, 4787, 7211, 9781
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OFFSET
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1,1
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COMMENTS
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L(m) = Lucas(m) = Fibonacci(m-1) + Fibonacci(m+1). 7 = L(4) divides L(4*(1+2m)) since L(4m) = L(4)*L(4*(m-1)) - L(4*(m-2)).
Integer k is in this sequence iff k is prime and 4k belongs to A085726. - Max Alekseyev, May 16 2010
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LINKS
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MATHEMATICA
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a=7; b=47; Do[ c=7b-a; a=b; b=c; If[ PrimeQ[c/7], Print[n] ], {n, 3, 100}]
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CROSSREFS
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Cf. A074304 (numbers k such that Lucas(2k)/3 is prime).
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KEYWORD
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less,more,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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