%I #18 Nov 03 2017 03:48:11
%S 4,5,6,7,10,11,15,16,34,44,63,66,168,427,575,928,1094,1218,1363,1713
%N Numbers n such that the denominator of n!/!n (= A000142(n)/A000166(n)) is prime.
%C That is, numbers n such that A053557(n) is prime. - _Michel Marcus_, Aug 28 2013
%t a[n_] := Sum[(-1)^k/k!, {k, 0, n}]; Select[Range[100], PrimeQ[Numerator[a[#]]] &] (* _G. C. Greubel_, Oct 31 2017 *)
%o (PARI) isok(n) = isprime(numerator(sum(k=0, n, (-1)^k/k!))); \\ _Michel Marcus_, Aug 28 2013
%Y Cf. A000142, A000166, A053557.
%K nonn,more
%O 1,1
%A _Ed Pegg Jr_, Jul 11 2008
%E a(16)-a(20) from _G. C. Greubel_, Nov 01 2017