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Minimal number of vertices in an n-polyomino.
1

%I #8 Aug 25 2021 16:53:18

%S 4,6,8,9,11,12,14,15,16,18,19,20,22,23,24,25,27,28

%N Minimal number of vertices in an n-polyomino.

%C It appears that a(n) = A080037[n] = n + Floor[Sqrt[4n-3]] + 2 for n>0.

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/Polyomino.html">Polyomino</a>.

%Y Cf. A080037.

%K nonn,more

%O 1,1

%A _Alexander Adamchuk_, Aug 12 2006

%E a(17)-a(18) from _John Mason_, Aug 14 2021