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%I #19 May 05 2023 01:38:51
%S 0,2,48,1080,13440,157500,1596672,15303288,138378240,1205095320,
%T 10161580000,83564769288,672880545792,5324077540600,41500141300800,
%U 319348194300000,2430018948833280,18309616752099420,136761272555846400,1013613060373960200,7460254139738400000
%N a(n) = n^3*binomial(2*n, n)*Fibonacci(n).
%H Robert Israel, <a href="/A119703/b119703.txt">Table of n, a(n) for n = 0..978</a>
%F Sum_{n>=0} a(n)/8^n = 479*sqrt(10)/8. - _Amiram Eldar_, May 05 2023
%p [seq((n^3*binomial(2*n, n))*combinat:-fibonacci(n), n=0..25)]; # corrected by _Robert Israel_, Sep 07 2014
%t Table[n^3 Binomial[2n,n]Fibonacci[n],{n,0,30}] (* _Harvey P. Dale_, Jan 14 2017 *)
%o (PARI) vector(50,n,(n-1)^3*(binomial(2*(n-1),n-1))*fibonacci(n-1)) \\ _Derek Orr_, Sep 07 2014
%Y Cf. A000984, A000045.
%K nonn,easy
%O 0,2
%A _Zerinvary Lajos_, Jun 09 2006
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