%I #23 Jun 10 2018 20:24:24
%S 3,2,0,6,2,2,4,1,1,3,3,4,1,9,0,9,0,6,1,4,2,9,5,9,0,6,1,1,3,2,1,7,1,9,
%T 0,9,0,4,4,2,2,4,1,1,2,1,8,1,2,2,1,1,4,2,3,1,2,1,2,1,1,1,1,2,1,9,4,8,
%U 1,2,7,1,2,9,0,2,1,6,1,1,2,1,2,3,2,9,0,4,2,9,0,2,1,6,8,3,1,5,2,1,2,1,1,1,2,1,4
%N A modified Trott constant.
%C Has the property that the continued fraction
%C [0; 3, 2, 0, 6, 2, 2, 4, 1, 1, 3, 3, 4, 1, 9, 0, 9, 0, 6, 1, 4, 2, 9, 5, 9, 0, 6, 1, 1, 3, 2, 1, 7, 1, 9, 0, 9, 0, 4, 4, 2, 2, 4, 1, 1, 2, 1, 8, 1, 2, 2, 1, 1, 4, 2, 3, 1, 2, 1, 2, 1, 1, 1, 1, 2, 1, 9, 4, 8, 1, 2, 7, 1, 2, 9, 0, 2, 1, 6, 1, 1, 2, 1, 2, 3, 2, 9, 0, 4, 2, 9, 0, 2, 1, 6, 8, 3, 1, 5, 2, 1, 2, 1, 1, 1, 2, 1, 4]
%C = 2841811577511303983409363256028316730642 / 8863421510947433793512472278725472500639
%C which is:
%C 0.32062241133419090614295906113217190904422411218122114231212111121948127129021611293319604592075099759507890...
%C giving us 81 decimal digits of agreement with
%C 0.32062241133419090614295906113217190904422411218122114231212111121948127129021611212329042902168315212111214...
%C However, there is no obvious methodology with which to get more terms.
%C For a non-obvious way to do this, see the Schoenfield link. - _Jon E. Schoenfield_, Apr 18 2010
%H Ed Pegg, Jr., <a href="http://mathpuzzle.com/">MathPuzzle</a> - see Dec 21 2005 column.
%H Jon E. Schoenfield, <a href="/A114376/a114376.txt">Extending (arbitrarily far) the modified Trott constant of A114376</a>
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/TrottConstants.html">Trott Constants</a>
%Y Cf. A039662.
%K nonn,cons
%O 0,1
%A _Hans Havermann_, Dec 23 2005