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Numbers k such that k^3 contains exactly 3 copies of each digit of k.
6

%I #22 Feb 28 2024 01:41:19

%S 87624375,88236519,516473892,569784132,576283194,623837409,652319574,

%T 726918453,751396842,865917402,876243750,882365190,908714352,

%U 984052317,996302784,4680215379,4721985066,4752360918,4765380219,4780620591,4816217505,4823206911,4857619623

%N Numbers k such that k^3 contains exactly 3 copies of each digit of k.

%C All terms are divisible by 3. - _Chai Wah Wu_, Feb 27 2024

%H Yi Yang, <a href="/A114259/b114259.txt">Table of n, a(n) for n = 1..7886</a>

%H Carlos Rivera, <a href="https://www.primepuzzles.net/puzzles/puzz_971.htm">Puzzle 971. The cube of N such that...</a>, The Prime Puzzles & Problems Connection.

%e 87624375 is in the sequence since its cube 672782675854638427734375 contains three 8's, six 7's, three 6's and so on.

%Y Cf. A114258, A114260, A114261, A199631.

%K base,nonn

%O 1,1

%A _Giovanni Resta_, Nov 18 2005