A110354 Beyond repair - see A245628 for a better version.

1, 2, 23, 3, 34, 4, 44, 5, 55, 56, 65, 6, 66, 67, 7, 77, 777, 8, 88, 89, 98, 888, 9, 99, 9999, 13

Offset

1,2

Comments

Original definition was: "Rearrangement of natural numbers such that digit 'd' occurs exactly 'd' times. Once a cycle is completed, i.e., 9 occurs 9 times. The same is repeated. The first number of the second cycle would be a number containing 1 once and which has not occurred earlier."

Why is the first number of the second cycle 13 and not 10? 10 is the next number after 1 that contains 1 once. How is the first number of the second cycle chosen? Also, in the given example it is stated "a(26) = 13 as 12 has already occurred", but 12 does not occur in the terms prior to a(26). - Felix Fröhlich, Jul 26 2014

Comments from Eric Angelini, Jul 27 2014, in response to my asking him to investigate this sequence. (Start)

Murthy's seq is incoherent, for many reasons but two are sufficient:

<1> DEFINITION

"Rearrangement of natural numbers [...]"

... No -- as "10" (or 100, 101, etc.) will never show up (because we would then not have zero "0"s)

<2> EXAMPLE

[...] "The second cycle starts at a(26) and a(26) = 13 as 12 has already occurred."

... No, 12 has not occurred yet.

... I propose the following definition and sequence ... (see A245628).

(End) - added by N. J. A. Sloane, Jul 27 2014

Links

Table of n, a(n) for n=1..26.

Crossrefs

See A245628 for a better version.

Sequence in context: A360534 A076653 A114008 * A245628 A162711 A120713

Adjacent sequences: A110351 A110352 A110353 * A110355 A110356 A110357

Keyword

dead

Author

Amarnath Murthy, Jul 22 2005

Status

approved