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A109783 a(n) is the largest possible K such that there exists a K-digit in base n integer M such that for each N=1,2,...,K, the integer given by the first N digits of M in base n is divisible by N. 3

%I #21 Aug 30 2021 10:51:46

%S 2,6,7,10,11,18,17,22,25,26,28,35,39,38,39,45,48,48,52,53,56,58,61,65,

%T 67,69,73,75,79,83,83

%N a(n) is the largest possible K such that there exists a K-digit in base n integer M such that for each N=1,2,...,K, the integer given by the first N digits of M in base n is divisible by N.

%C Length of the largest polydivisible number in base n.

%H A. Mihailovs, <a href="http://beta.mapleprimes.com/blog/alec/ponder_this">Ponder This</a>.

%H Wikipedia, <a href="https://en.wikipedia.org/wiki/Polydivisible_number">Polydivisible number</a>.

%F Conjecture 1: a(n) is finite for all n>1. Conjecture 2: a(n) ~ n*e.

%F a(n) = 1 + floor( log(A109032(n)) / log(n) ). - _Max Alekseyev_, Sep 19 2009

%e a(10)=25 because for 25-digit number 3608528850368400786036725, 3 is divisible by 1, 36 is divisible by 2, 360 is divisible by 3, ..., 3608528850368400786036725 is divisible by 25 and there is no 26-digit number with similar properties.

%p a:=seq(nops(convert(A109032[i],base,i+1)),i=1..nops(A109032)); # _Martin Renner_, Apr 05 2016

%Y Cf. A109032.

%K base,more,nonn

%O 2,1

%A Alec Mihailovs (alec(AT)mihailovs.com), Aug 13 2005

%E a(24)-a(32) from _Karl W. Heuer_, Jan 08 2015

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