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%I #2 Mar 30 2012 17:37:53
%S 1,6,11,25,51,113,230,491,987,2019
%N Location of first occurrence of n consecutive 0's in A108737.
%e A108737 begins 0,1,0,1,1,0,0,1,1,1,0,0,0,1,0,1,0,... The first occurrence of 3 consecutive 0's is at term 11, so a(3)=11.
%Y Cf. A108737, A109295.
%K nonn
%O 1,2
%A _John W. Layman_, Jun 24 2005
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