%I #19 Dec 18 2012 10:47:43
%S 1,1,11,111,11111,11111111,1111111111111,111111111111111111111,
%T 1111111111111111111111111111111111,
%U 1111111111111111111111111111111111111111111111111111111,11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111
%N Concatenation of the previous pair of numbers, with the first two terms both 1.
%C The Fibonacci numbers, A000045, represented in base 1 (see A000042).
%F a(n) = (10^A000045(n)-1)/9.
%F a(n) = A000042(A000045(n)).
%e The third term is 11 which is the concatenation of the first two terms 1 and 1.
%Y Column b=1 of A214326.
%Y Column k=1 of A214679.
%Y Cf. A037842, A131293.
%K nonn,easy,base
%O 1,3
%A _Parthasarathy Nambi_, Jun 01 2005
%E Edited by _Jason Kimberley_, Dec 15 2012