A107362 Sequence A={a(n),n=0,1,2,3,...} such that the subsequence S1={a(n)|n mod 5=0,3} is identical to A and S2=S\S1 (the complement of S1 in A) is identical to A except with the first term omitted.

1, 2, 1, 2, 2, 1, 2, 1, 2, 2, 2, 1, 2, 1, 2, 2, 2, 1, 1, 2, 2, 1, 2, 2, 2, 2, 2, 1, 1, 1, 2, 2, 2, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 1, 1, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 2, 2, 2, 2, 2, 1, 2, 1, 2, 1, 2, 1, 2, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2

Offset

0,2

Links

Table of n, a(n) for n=0..104.

Formula

a(0)=1, a(1)=2, a(2)=1 and, for n>2, a(n)=a(2[n/5] if n=0 mod 5, a(n)=a(n-2[n/5]) if n=1, 2 mod 5, a(n)=a(2[n/5]+1) if n=3 mod 5 and a(n)=a(n-2[n/5]-1) if n=4 mod 5.

Example

S1={a(0),a{3),a(5),a(8),a(10),...}={1,2,1,2,2,...}=A. Similarly for A\S1.

Crossrefs

Sequence in context: A001468 A014675 A308186 * A166332 A022303 A113189

Adjacent sequences: A107359 A107360 A107361 * A107363 A107364 A107365

Keyword

eigen,nonn

Author

John W. Layman, May 24 2005

Status

approved