%I
%S 0,0,1,1,2,2,1,1,2,4,5,5,4,2,1,3,6,8,9,9,8,6,3,1,4,8,11,13,14,14,
%T 13,11,8,4,1,5,10,14,17,19,20,20,19,17,14,10,5,1,6,12,17,21,24,26,
%U 27,27,26,24,21,17,12,6,1,7,14,20,25,29,32,34,35,35,34,32,29,25,20,14,7,1,8,16,23,29,34,38,41,43,44,44,43,41,38,34,29,23
%N a(1)=a(2)=0, a(n) = abs(2*a(n1)  a(n2))  1.
%C A jumping flea sequence. The nth jump is starting at index n(n+2) and is ending at (n+1)(n+3). It reaches the altitude of n(n+3)/2 and can be given directly (omitting the 1's). For instance, for the 4th jump: start with 4, then add (40)=4 to 4 which gives 8, then add (41)=3 to 8 giving 8+3=11, then 11+(42)=13, then 13+(43)=14. By symmetry you get the complete 4th jump: {4,8,11,13,14,14,13,11,8,4}.
%F for any s>0 sum(k=s*(s+2), (s+1)*(s+3), a(k) )=1/3*(s+2)*(s+3)*(2*s1)=2*A058373(s).
%F a(n) = (1/2)*(n1f(n+2)^2) where f(n)=floor(1/2+sqrt(n))abs{n1floor(1/2+sqrt(n))^2}.  _Benoit Cloitre_, Mar 17 2005
%o (PARI) a(n)=if(n<3,0,abs(2*a(n1)a(n2))1)
%K sign
%O 1,5
%A _Benoit Cloitre_, Mar 09 2005
