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A100465
Let p(1)=2, p(2)=3, p(3)=5, ... denote the primes and let E(n) = 1 + p(1) * p(2) * ... * p(n). Sequence gives primes p such that p(n+2) | E(n).
1
7, 271, 307, 673
OFFSET
1,1
COMMENTS
No other terms for p < 80000000.
EXAMPLE
7 is a term of the sequence, because it is the 4th prime and divides E(2)=2*3+1=7 trivially. - Martin Ehrenstein, Feb 05 2021
CROSSREFS
See A066735 for further information.
Cf. A006862 Euclid numbers.
Sequence in context: A015089 A179565 A069449 * A140031 A066413 A332127
KEYWORD
nonn,more
AUTHOR
Lévai Gábor (gablevai(AT)vipmail.hu), Nov 23 2004
EXTENSIONS
a(2) corrected by Martin Ehrenstein, Feb 05 2021
STATUS
approved