|
EXAMPLE
|
From the table of powers of A(x), we see that
4^n/2 = Sum of coefficients [x^0] through [x^n] in A(x)^n:
A^1=[1,1],2,2,0,-4,-6,2,22,30,-26,...
A^2=[1,2,5],8,8,0,-16,-24,8,88,120,...
A^3=[1,3,9,19],30,30,2,-54,-84,20,288,...
A^4=[1,4,14,36,73],112,112,16,-176,-288,32,...
A^5=[1,5,20,60,145,281],420,420,90,-570,-988,...
A^6=[1,6,27,92,255,582,1085],1584,1584,440,-1848,...
A^7=[1,7,35,133,413,1071,2331,4201],6006,6006,2002,...
A^8=[1,8,44,184,630,1816,4460,9320,16305],22880,22880,...
the main diagonal of which is:
[x^n]A(x)^(n+1) = (n+1)*A081696(n) for n>=0.
|