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Triangle T(n,k) read by rows, T(n, k) = binomial(2*k, k)*binomial(n, k), 0<=k<=n.
5

%I #34 Jul 04 2023 09:33:37

%S 1,1,2,1,4,6,1,6,18,20,1,8,36,80,70,1,10,60,200,350,252,1,12,90,400,

%T 1050,1512,924,1,14,126,700,2450,5292,6468,3432,1,16,168,1120,4900,

%U 14112,25872,27456,12870,1,18,216,1680,8820,31752,77616,123552,115830

%N Triangle T(n,k) read by rows, T(n, k) = binomial(2*k, k)*binomial(n, k), 0<=k<=n.

%C This sequence gives the coefficients of the Jensen polynomials (increasing powers of x) of degree n and shift 0 for the central binomial sequence A000984. For a definition of Jensen polynomials see a comment in A094436. - _Wolfdieter Lang_, Jun 25 2019

%H Indranil Ghosh, <a href="/A098473/b098473.txt">Rows 0..125, flattened</a>

%H O. T. Dasbach, <a href="http://www.combinatorics.org/ojs/index.php/eljc/article/view/v15i1n5">A natural series for the natural logarithm</a>, Electronic Journal of Combinatorics, (15) 2008 #N5.

%F T(n, k) = binomial(2*k, k)*binomial(n, k).

%F Sum_{k=0..n} T(n,k)*x^(n-k) = A126869(n), A002426(n), A000984(n), A026375(n), A081671(n), A098409(n), A098410(n) for x = -2, -1, 0, 1, 2, 3, 4 respectively. - _Philippe Deléham_, Sep 28 2007

%F From _Peter Bala_, Jun 06 2011: (Start)

%F O.g.f.: 1/sqrt(1 - t)*1/sqrt(1 - t*(1 + 4*x)) = 1 + (2*x + 1)*t + (1 + 4*x + 6*x^2)*t^2 + ....

%F Let R_n(x) denote the row generating polynomials of this triangle, which begin

%F R_1(x) = 1 + 2*x, R_2(x) = 1 + 4*x + 6*x^2, R_3(x) = 1 + 6*x + 18*x^2 + 20*x^3.

%F Dasbach gives the following slowly converging series for the logarithm function:

%F log(x) = Sum_{n >= 1} 1/n*R_n(-1/x), valid for x >= 4.

%F The polynomials (1 - x)^n*R_n(x/(1 - x)) appear to be the row polynomials of A135091 (see also A171128). (End)

%e Rows begin

%e 1;

%e 1, 2;

%e 1, 4, 6;

%e 1, 6, 18, 20;

%e 1, 8, 36, 80, 70;

%e 1, 10, 60, 200, 350, 252;

%p A098473 := proc(n,k) binomial(2*k,k)*binomial(n,k) ; end proc:

%t Table[Binomial[2k,k]Binomial[n,k],{n,0,10},{k,0,n}]//Flatten (* _Harvey P. Dale_, Aug 15 2020 *)

%o (PARI): T(n,k)=binomial(2*k, k)*binomial(n, k);

%o for(n=0,10,for(k=0,n,print1(T(n,k),", "));print()); /* as triangle */

%Y Row sums are A026375.

%Y Antidiagonal sums are A026569.

%Y Principal diagonal is A000984.

%Y Cf. A002426, A081671, A098409, A098410, A094436, A126869.

%K easy,nonn,tabl

%O 0,3

%A _Paul Barry_, Sep 09 2004