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%I #1 Feb 19 2004 03:00:00
%S 1,0,2,0,0,0,2,0,8,0,3,0,0,0,0,0,0,0,0,0,14,0,0,0,0,0,26,0,6,0,0,0,11,
%T 0,0,0,10,0,0,0,16,0,15,0,0,0,25,0,4,0,45,0,0,0,0,0,20,0,51,0,45,0,0,
%U 0,0,0,2,0,35,0,22,0,0,0,0,0,21,0,0,0,0,0,81,0,0,0,6,0,0,0,0,0,66,0,0,0,13
%N Minimum number of consecutive previous nonnegative integers to n that must be concatenated together in ascending order such that n divides the concatenated term, or zero if n divides no such concatenation.
%C Concatenation always end at n-1 and cannot start further than n-n (zero). Hence the maximum value of a(n) is n.
%e a(7) = 2 because 7 will divide the number formed by concatenating the 2 integers prior to 7 in ascending order (i.e. 56). a(6) = 0 because 6 will not divide 5, 45, 345, 2345, 12345, or 012345.
%Y Cf. A088797, A088799, A088868, A088870, A088872, A088885.
%K base,nonn
%O 1,3
%A Chuck Seggelin (barkeep(AT)plastereddragon.com), Oct 29 2003
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