%I #10 Jun 28 2019 14:48:18
%S 64,160,304,464,680,904,1144,1468,1804,2156,2516,2916,3332,3818,4322,
%T 4850,5390,5934,6494,7094,7702,8326,9055,9791,10547,11331,12123,12933,
%U 13749,14589,15469,16369,17281,18209,19145,20137,21137,22177,23281
%N Sum of first n 6-almost primes.
%C The first two elements in this sequence are themselves 6-almost primes. a(1) = 64 = 2^6. a(2) = 160 = 2^5 * 5. - _Jonathan Vos Post_, Dec 11 2004
%H Robert Israel, <a href="/A086052/b086052.txt">Table of n, a(n) for n = 1..10000</a>
%e a(2)=160 because sum of first two 6-almost primes, i.e. 64+96, is 160.
%p ListTools:-PartialSums(select(numtheory:-bigomega=6, [$1..2000])); # _Robert Israel_, Jun 28 2019
%t Accumulate[Select[Range[1500],PrimeOmega[#]==6&]] (* _Harvey P. Dale_, May 15 2013 *)
%Y Partial sums of A046306.
%K easy,nonn
%O 1,1
%A _Shyam Sunder Gupta_, Aug 24 2003